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Integrate the following functions 1/(x+x...

Integrate the following functions `1/(x+xlogx)`

Text Solution

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Put 1+logx = t. Then dt = 1/x dx
therefore `int 1/(x+xlogx) dx = int 1/(1+logx)x) dx`
`int 1/t dt = log|t| +c`
=`log|1+logx| +c`
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