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Integrate the following functions 1/(1-t...

Integrate the following functions 1/(1-tanx)

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1/(1-tanx) = cosx/(cosx-sinx)
`1/2[((cosx-sinx)-(-sinx-cosx))/(cosx-sinx)]`
=`1/2[1-(-sinx-cosx)/(cosx-sinx)]`
therefore` int dx/(1-tanx)`
=`1/2 [x-log|cosx-sinx|]+c`
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