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Integrate the following functions (3x^2)...

Integrate the following functions `(3x^2)/(x^6+1)`

Text Solution

Verified by Experts

Let t = `x^3`. Then `dt = `3x^2 dx`
therefore` int (3x^2)/(x^6+1) dx`
=`int dt/(t^2+1) = tan^-1 t+c`
=`tan^-1(x^3)+c`
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