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Integrate the following functions 1/sqrt...

Integrate the following functions `1/sqrt(x^2+2x+2)`

Text Solution

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`x^2+2x+2 = (x+1)^2+1`
therefore` int1/sqrt(x^2+2x+2) dx`
=`int 1/sqrt((x+1)^2+1) dx`
=`log|(x+1) + sqrt((x+1)^2+1)|+c`
=`log |x+1+sqrt(x^2+2x+2)|+c`
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