Integrating the following functions `((x-3) e^x)/(x-1)^3`

Explanation

`int ((x-3) e^x)/(x-1)^3 dx = int ((x-1)-2)/(x-1)^3 e^x dx`
=`int (1/(x-1)^2- 2/(x-1)^3)e^x dx`
`e^x/(x-1)^2+c, f(x) = 1/(x-1)^2`
`f^.(x) = -2/(x-1)^2`