Using properties evaluate the following definite integrals,
evaluate the following: `int_0^4 |x-1| dx`

Explanation

`int_0^a f(x) g(x) dx = int_0^a f(a-x) g(a-x)dx`
=`int_0^a f(a-x) [4- g(x)]dx`
=`int_0^a 4 f(a-x) dx - int_0^a f(a-x) g(x) dx`
=`4 int_f(a-x)dx - int_0^a f(x) g(x) dx`
`gt 2 int_0^a f(x) g(x) dx = 4 int_0^a f(a-x)dx`
= `4 int_0^a f(x) dx`
Thus, `int_0^a f(x) g (x) dx = 2 int_0^a f(x) dx`