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Verify that the given function (explicit or implicit) isa solution of the correseponding differential equation : `y = e^x + 1` : y'' - y' = 0

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` y = e^x + 1`
`rArr y. = e^x`
`rArr y.. = e^x = y.`
`therefore y.. - y. = 0 `
Therefore, `y = e^x + 1` is a solution of y.. - y. = 0
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