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Find the cartesian equation fo the following planes. `vecr.(hati+hatj-hatk)=2`

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The correct Answer is:
Replacing `vecr` by `xhati+yhatj+zhatk` we have `(xhati+yhatj+zhatk).(hati+hatj+hatk) = 2` i.e., x+yz=2, which is the cartesian equation of the plane
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