Find the co-ordinates of the foot of the perpendicular drawn from the origin. 5y + 8 = 0

Answer

The direction cosines of the normal to the plane are 0, -1, 0 and the distance of the plane from the origin is `8/5` (see example 1 (d) above)
`therefore` The co-ordinates of the foot of the perpendicualr `= (0, (-8)/5, 0)`