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In the following cases, find the distanc...

In the following cases, find the distance of each of the given point from the corresponding given plane
(0,0,0) : 3x-4y+12z = 3

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The correct Answer is:
The given plane is 3x-4y+12z-3=0 `therefore` The required distance = `absabs((3xx0-4xx0+12xx0-3)/(sqrt(3^2+(-4)^2+12^2)) = abs((-3)/(sqrt(9+16+144)) = 3/13`
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A N EXCEL PUBLICATION-THREE DIMENSTIONAL GEOMETRY-QUESTION BANK
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