A cubical iron block is given a charge of+40mC and placed in vacuum. Calculate the net flux due to the charged cube through one face.

A cubical iron block is given a charge of+40mC and placed in vacuum. Will there be any change in the flux if it is placed under water of dielectric constant 81. Justify.

A spherical Gaussian surface encloses a charge of 8.85 xx 10^(-8),C . (i) Calculate the electric flux passing through the surface (ii) If the radius of the Gaussian surface is doubled, how would the flux change?

Imagine that a charge .q. is situated at the centre of a hollow cube. What is the electric flux through one side of the cube?

A point charge Q is place at the center of a cube of side, l lthe electric flux emerging the cube is

A point charge of 2muC is placed at the centre of a cubic Gaussian surface of side 0.5 cm. What is the net flux through the surface? (Given varepsilon_0 , = 8.85x 10^-12C^2 /N/M^2 )

A point charge +10 muC is a distance 5cm directly above the centre of a square of side 10cm as shown in the figure. What is the magnitude of the electric flux through the square? [Hint: Think of the square as one face of cube with edge 10cm]. '(##VPU_HSS_PHY_XII_CO1_E02_018_Q01##)'