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You find a sealed box on your door step....

You find a sealed box on your door step. You sus pect that the box contain charged metal spheres packed in insulating material. Br Which law explains relation between charge of spheres and electric flux.

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You find a sealed box on your door step. You sus pect that the box contain charged metal spheres packed in insulating material. Br State the law.

You find a sealed box on your door step. You sus pect that the box contain charged metal spheres packed in insulating material. Br Give a mathematical proof for this law.

You find a sealed box on your door step. You suspect that the box contain charged metal spheres packed in insulating material. Br Using this law, can you estimate the total charge inside the box without opening the box?

A charged metallic sphere A is suspended by a nylon thread. Another charged metallic sphere B held by an insulating handle is brought close to 'A' such that the distance between their centres is 10cm as shown in the figure (a). The resulting repulsion of A is noted (for example, by shining a beam of light and measuring the deflection of its shadow on a screen). Spheres A and B are touched by uncharged spheres C and D respectively as shown in the fig (b). C and D are then removed and B is brought closer to A to a distance of 5.0cm between their centres as shoen in the fig(c). What is the expected repulsion of A on the basis of Coulomb's law? Spheres A and C and spheres B and D have identical sizes. Ignore the sizes of A and B in comparison to the separation between their centres. '(##VPU_HSS_PHY_XII_CO1_E01_005_Q01##)'

Figure represent an infinite sheet of charge of surface charge density sigma . You have to find electric field Intensity at P due to this infinite charge. br Can you apply Coulomb.s Inverse square law to find electric field at P?

A metal sphere of radius R carrying q (+ve) charges is shown in the figure. br Draw the electric lines of force related to this metal sphere.

In symmetric charge configurations, the electric field can be easily calculated using Gauss’s law. A sphere of radius ‘a‘ is made of Insulating material and has charge distributed uniformly throughout its volume. Let the charge density be rho . Find the field due to the charge for rlea .

Careful measurement of the electric field at the surface of a black box Indi-cates that the net outward flux through the surface of the box is 8.0 xx 10^3Nm^2C :- If the net outward flux through the surface of the box were zero, could you conclude that there were no charges Inside the box? Why or why not?