A parallel plate capacitor with air between the plates has a capacitance of 8pF (`1pF=10^-12F`). What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant s.

A parallel plate capacitor with air between the plates has a capacitance of 8µF. What will be the capacitance if the distance between the plates is reduced by half and the space between is filled with a medium of dielectric constant 5?

How capacitance changes if the distance between the plates of a parallel plate capacitor is halved?

In parallel plate capacitor with air between the plates, each plate has an area of 6 xx 10^3m^2 and the distance between the plates is 3mm. Calculate the capacitance of the capacitor if it is connected to 100V supply.What is the charge on each plate of the capacitor?

Derive an expression for capacitance of the above capacitor with the dielectric slab in between the plates

A parallel plate capacitor with oil between the plates (dielectric constant of oil, k = 2) has a capacitance C. If the oil is removed, then capacitance of the capacitor is ...(a)√ 2 C (b)2C (c)C √ 2 (d)C 2