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Determine the wavelength and frequency of the radiation having the longest wavelength in Lyman series of hydrogen atom.

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Among the photoelectrons, emitted due to incidence of light of frequency f on a metal surface , only the electrons having the highest kinetic energy can ionise a hydrogen atom. If this experment is performed with light of frequency 5/6f , the photoelectron having the highest kinetic energy can excite a hydrogen atom and from this excited hydrogen atom a photon of wavelength 1215 Å is emitted . Determine the (i) work function of the metal and

Among the photoelectrons, emitted due to incidence of light of frequency f on a metal surface , only the electrons having the highest kinetic energy can ionise a hydrogen atom. If this experment is performed with light of frequency 5/6f , the photoelectron having the highest kinetic energy can excite a hydrogen atom and from this excited hydrogen atom a photon of wavelength 1215 Å is emitted . Determine the (ii) value of f. Given h=6.625 xx10^(-34)*s,c=3xx10^(8)*s^(-1), 1 eV=1.6 xx10^(-19)J , ionisation energy of hydrogen =13.62 eV.

if the shortest wavelength of H-atom in Lyman series is X, then longest wavelength in Paschen series of He^(+) is-

Calculate the wavelength of radiations in the Lyman series when an electron falls from fourth stationary state of hydrogen atom: (R_H=1.1xx10^7m^-1)

What do you mean by 'Dual nature of electron? Derive De-Broglie's equation. Calculate the wavelength of the radiation emitted, producing a line in the Lyman series when an electron falls from fourth stationary state in hydrogen atom. (R_H = 1.1xx10^7m^-1)

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