Prove that in ’n’th shell `2n^2` number of electron,can be accomodated.

How would you show that the maximum number of electrons that can be accommodated in an orbit with principal quantum number 'n' is 2n^(2) ?

What is the maximum number of electrons that can be accommodated in the 2p-sub-shell? Give reason in favour of your answer.

Show that at most eight electrons can be accommodated in n = 2.

What is the maximum number of electrons in the 'n' th orbit?

1 mol N_(2)H_(4) loses 10 mol of electrons with th electrons with the formation of I mol of a new compound y. of the new compound contains same number of N- atoms then what will be the oxidation number of nitrogen in the new compound ? (Assume that the oxidation number of H -atom does not change)

The total number of ways in which n^2 number of identical balls can be put in n numbered boxes (1,2,3,.......... n) such that ith box contains at least i number of balls is a. .^(n^2)C_(n-1) b. .^(n^2-1)C_(n-1) c. .^((n^2+n-2)/2)C_(n-1) d. none of these

Prove that (n !+1) is not divisible by any natural number between 2 and n

An atom of an element contains 2 electrons in the first shell (n=1), 8 electrons in the second shell (n=2) and 5 electrons in the third shell (n=3). There are 16 neutrons in the nucleus of the atom. From these data, find (1) the atomic no. of the element, (2) the no. of s and p-electrons int he atom, (3) mass no. of the element.

Prove that [(n+1)//2]^n >(n !)dot

What is the potential energy of an electron present in N-shell of the Be^(+3) ion?