Find the first ionization energy of hydorgen atom given `E_1 =- 13.38ev`

Hydrogen atom in its ground state, is excited by means of monochromatic radiation of wavelength 975 Å . How many different lines are possible in the resulting spectrum ? Calculate the longest wavelength amongst them. Given, ionisation energy of hydrogen atom is 13.6 eV.

Determine the value of the de Broglie wavelength associated with the electron orbiting in the ground state of hydrogen atom ( given E_(n) = - (13.6//n^(2))eV and bohr radius r^(0) = 0.53Å ). How will the de Broglie wavelength change when it is in the first excited state?

The ionization energy of the hydrogen atom is 13.6eV. The potential energy of the electron in n=2 state of hydrogen atom is

Given the value of ground state energy of hydrogen atom as -13.6 eV. Find out its kinetic and potential energy in the ground and second excited states.

Compared to first ionization enthalpy of an atom, the second is :

The first ionisation energy of H and He are 13.6eV and 24.6eV respectively how much energy would be given out during the formation of ground state of He atom from He^2+ nucleus if combines with two electrons?

The ionisation energy of a hydrogen atom is 13.6 eV. Estimate the energy required to excite it from its ground state to the next state.

In case of hydrogen atom, calculate the wavelength of K_(alpha) line. Given energy of hydrogen atom in ground state =-13.6 eV,h=6.63xx10^(-34)j*s .

The total energy of an electron in the first excited state of the hydrogen atom is about -3.4 eV . In this state (a) what is the kinetic energy of the electron ?

The total energy of an electron in the first excited state of the hydrogen atom is about -3.4 eV . In this state (b) what is the potential energy of the electron ?