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0n^1 rightarrow 1p^1+1e^0+ vartheta^- ...

`_0n^1 rightarrow _1p^1+_1e^0+ vartheta^-`
If a proton splits in a nucleus what are the changes. Represent it with an equation.

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_0n^1 rightarrow _1p^1+_-1e^0+ vartheta^- What happens to the parent nucleus after the process?

_0n^1 rightarrow _1p^1+_-1e^0+ vartheta^- Which process is represented by the equation?

_0n^1 rightarrow _1p^1+_-1e^0+ vartheta^- After this process the nucleus will be in a higher energy state. How will it come to ground state?

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If the pairs of lines x^(2) - 2nxy -y^(2) =0 and x^(2) - 2mxy -y^(2) =0 are such that one of them represents the bisector of the angles between the other , then a): (1)/(n) +(1)/(m) =0 b) (1)/(n) - (1)/(m) =0 c) nm-1 =0 d) nm+1=0

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