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KALYANI PUBLICATION-LOGARITHMS-EXERCISE
- Assuming the base as 10,prove that (log3sqrt3+log2sqrt2-log5sqrt5)/l...
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- If logp/(b-c)=logq/(c-a)=logr/(a-b),then prove that p^a.q^b.r^c=1
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- If logx/(a+b-2c)=logy/(b+c-2a)=logz/(a+c-2b), then prove that xyz=1
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- If frac(xylog(xy))(x+y)=frac(yzlog(yz))(y+z)=frac(zxlog(zx))(z+x) then...
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- If logx/(y-z)=logy/(z-x)=logz/(x-y) prove that xyz=1
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- If (3.7)^x=(.37)^y=1000,then prove that 1/x-1/y=1/3
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- If a^2+b^2=23ab,then prove that log((a+b)/5)=1/2(log a+log b)
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- If x^2+y^2=7xy,then prove that log(x+y)=log3+1/2(logx+logy)
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- If x^2+y^2=11xy,then prove that log((x+y)/13)=1/2(logx+logy)
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- If a^2+b^2=18ab,then prove that log((a-b)/4)=1/2(loga+logb)
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- If 4a^4+9b^4=37a^2b^2,then prove that log(2a^2+3b^2)=loga+logb+log7
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- If 2log(a+b)=loga+logb+log8,then prove that (a+b)^2=8ab
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- If log((x+y)/3)=1/2(logx+logy),then prove that x/y+y/x=7
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- If log((a+2b)/4)=1/2(loga+logb),then prove that a^2+4b^2=12ab
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- If log((x+y)/2)=1/2(logx+logy),then prove that x=y
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- Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 5-.6990,log...
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- Given that log10 2=.3010,log10 3=.4771,find the value of log10 12
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- Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 5-.6990,log...
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- Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 5-.6990,log...
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- Given that log10 2=.3010,log10 3=.4771,then find the value of log10 (...
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