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If log((x+y)/2)=1/2(logx+logy),then prov...

If `log((x+y)/2)=1/2(logx+logy)`,then prove that `x=y`

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KALYANI PUBLICATION-LOGARITHMS-EXERCISE
  1. If log((x+y)/3)=1/2(logx+logy),then prove that x/y+y/x=7

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  2. If log((a+2b)/4)=1/2(loga+logb),then prove that a^2+4b^2=12ab

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  3. If log((x+y)/2)=1/2(logx+logy),then prove that x=y

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  4. Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 5-.6990,log...

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  5. Given that log10 2=.3010,log10 3=.4771,find the value of log10 12

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  6. Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 5-.6990,log...

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  7. Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 5-.6990,log...

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  8. Given that log10 2=.3010,log10 3=.4771,then find the value of log10 (...

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  9. Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 5-.6990,log...

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  10. Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 7=.8450,log...

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  11. Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 7=.8450,log...

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  12. Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 5-.6990,log...

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  13. Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 5-.6990,log...

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  14. Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 7=.8450,log...

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  15. Given that log10 2=.3010,log10 3=.4771,then find the value of log10 3...

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  16. Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 7=.8450,log...

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  17. Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 5-.6990,log...

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  18. Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 5-.6990,log...

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  19. Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 7=.8450,log...

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  20. Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 7=.8450,log...

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