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KALYANI PUBLICATION-LOGARITHMS-EXERCISE
- If log((x+y)/2)=1/2(logx+logy),then prove that x=y
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- Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 5-.6990,log...
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- Given that log10 2=.3010,log10 3=.4771,find the value of log10 12
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- Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 5-.6990,log...
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- Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 5-.6990,log...
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- Given that log10 2=.3010,log10 3=.4771,then find the value of log10 (...
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- Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 5-.6990,log...
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- Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 7=.8450,log...
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- Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 7=.8450,log...
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- Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 5-.6990,log...
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- Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 5-.6990,log...
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- Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 7=.8450,log...
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- Given that log10 2=.3010,log10 3=.4771,then find the value of log10 3...
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- Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 7=.8450,log...
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- Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 5-.6990,log...
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- Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 5-.6990,log...
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- Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 7=.8450,log...
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- Given that log10 2=.3010,log10 3=.4771,log10 4=.6021,log10 7=.8450,log...
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- Prove that loga x+log(1/a) x=0
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- Prove that log3 2=log9 4=log27 8
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