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KALYANI PUBLICATION-LOGARITHMS-EXERCISE
- Prove that 1/(log(a/b) x)+1/(log(b/c) x)+1/(log(c/a) x)=0
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- Prove that 1/(loga P)+1/(logb P)+1/(logc P)=1/(logx P) where, abc=x
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- Prove that loga m+log(a^2) m^2+log(a^3) m^3+…..+log(a^p) m^p=p loga ...
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- Prove that loga x.logb a.logc b.logx c=1
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- Prove that loga x.logb y=logb x.loga y
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- Prove that (logab x)/(loga x)=1+logx b
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- Prove that loga (ab)+logb (ab)=loga (ab).logb (ab)
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- Prove that 1/4ltlog10 2lt1/3
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- Prove that 3/10ltlog10 2lt1/3
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- Prove that 1/3ltlog10 3lt1/2
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- Prove that 5/6<log10 7<6/7.
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- Solve the following equation : log x+log3+3log 2=2log4
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- Solve the following equation : logx/log4=log64/log16
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- Solve the following equation : logx 2+logx 4+logx 8+logx 16=10
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- Solve the following equation : log2 x+log4 x+log16 x=21/24
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- Solve the following equation : log2 x+log16 x=15
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- Solve the following equation : log3 x+log9 (x^2)+log27 (x^3)=3
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- Solve the following equation : log8 x+log4 x+log2 x=11
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- Solve the following equation : log4 x+log2 x=6
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- Solve the following equation : logx 3+logx 9+logx 729=9
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