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KALYANI PUBLICATION-HARDER PRODUCT AND FACTORISATION -EXERCISE
- Resolve into factors (b-c)^3+(c-a)^3+(a-b)^3
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- Resolve into factors b^2c^2(b-c)+c^2a^2(c-a)+a^2b^2(a-b)
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- Resolve into factors a^6(b^4-c^4)+b^6(c^4-a^4)+c^6(a^4-b^4)
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- Resolve into factors a^4b^4(a^2-b^2)+b^4c^4(b^2-c^2)+c^4a^4(c^2-a^2...
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- Resolve into factors xy(z^2+1)+z(x^2 + y^2 )
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- Resolve into factors 2b^2c^2y^2z^2+2c^2a^2z^2x^2+2a^2b^2x^2y^2-a^4x^...
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- Resolve into factors 72y^2z^2+18z^2x^2+8x^2y^2-x^4-16y^4-81z^4
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- Prove that x^3+8y^3-27z^3+18xyz = (x+2y-3z)(x^2+4y^2+9z^2+3xz+6yz-2x...
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- Prove that a^6+8a^3+27-18a^3=(a^2+2a+3)(a^4+4a^2+9-2a^3-6a-3a^2)
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- Prove that (x-y)^3+(y-z)^3+(z-x)^3=3(x-y)(y-z)(z-x)
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- Prove that (a+b+c)^3-(a^3+b^3+c^3)=3(b+c)(c+a)(a+b)
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- Prove that (a-b)^3+(b-c)^3+(c-a)^3=3(a-b)(b-c)(c-a)
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- if x+y+z=0,then Prove that (xyz)/((x+y)(y+z)(z+x))=-1 where(x!=-y,y!...
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- Prove that If a=2, b=3, c=5. Then prove that 2b^2c^2+2c^2a^2+2a^2b...
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- Prove that If 3x+2y=-1, then prove that 81x^4+16y^4+1-72x^2y^2-18x...
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- If x-y=7and xy=9, then find the value of (x^2+y^2)
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- Prove that 4x^2(y-z)+y^2(2x-z)+z^2(2x+y)-4xyz = (2x+y)(y-z)(2x-z)
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- Prove that (x-a)^2/((a-b)(a-c))+(x-b)^2/((b-a)(b-c))+(x-c)^2/((c-a)(...
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- Prove that 1/(a(a-b)(a-c))+1/(b(b-c)(b-a))+1/(c(c-a)(c-b))=1/(abc)
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- Prove that a/(bc(a-b)(a-c))+b/(ca(b-c)(b-a))+c/(ab(c-a)(c-a))=1/(abc...
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