Home
Class 11
PHYSICS
While measuring acceleration due to grav...

While measuring acceleration due to gravity by a simple pendulam a student makes a positive error of 1% in length and a negetive error of 3% in the value of timeperiod . The actual percentage of error in the measurement is

A

0.02

B

4

C

7

D

0.1

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • LAWS OF MOTION

    BINA LIBRARY|Exercise EXERCISE|20 Videos

  • OSCILLATIONS

    BINA LIBRARY|Exercise EXERCISE|75 Videos

Similar Questions

Explore conceptually related problems

The density of a material of a cube is calculated by measuring its mass and side . The error in measurement of mass and side are respectively 4% and 3%. Then the maximum percentage of error in measurement of density is

The radius of sphere is measured with an error of 2% what will be the error in its volume ?

A simple pendulam completes 20 oscillations in 25 S . The time is measured with a stop watch of least count 0.1 S . The error in the measurement is

For the determination of 'g' using a simple * pendulum, measurements of l and T are required. Error in 'the measurement of which of these will have larger effect on the value of 'g' thus obtained and why? What is done to minimize this error?

What is the % error in measurement of T of a pendulum if maximum errors in measurements of length and ‘g’ are 2% and 4% respectively ?

If the maximum error in the measurement of the radius of a sphere is 2% then what is maximum error in the calculation of volume?

A pendulum clock shows accurate time. If its length is increased by 0.4%, calculate the•error in time per day.

The measured mass and volume of a body are 22.42 g and 4.7 cm ^3 the possible errors in measuements of mass and volume are respectively 0.01 g and 0.1 cm ^3 The maximum error in density is about

The percentage errors in measurement of mass and velocity are 2 % and 3% resoectively . How much will be the maximum wrror in estimate of kinetic energy , obtained by measuring mass and velocity ?

A physical quantity P is related to four observables a, b, c and d as follows: P=( a^3b^2 )/(sqrtcd) The percentage errors of measurement in a, b, c and d are 1%,3%, 4% and 2%, respectively. What is the percentage error in/the quantity P? If the value of P calculated using the above relation turns out to be 3.763, to what value should you round off the result?