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A cell of emf 4V and internal resistance...

A cell of emf 4V and internal resistance 0.5 is connected across a load resistance (i) 7.52, (ii) 11.50, calculate (i) the ratio of difference in emf of the cell and the potential drop across the load.(ii) the ratio of current in the two cases.

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BINA LIBRARY-CURRENT ELECTRICITY-EXERCISE
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  2. A cylindircal metallic wire is stretched to increse its length by 5%. ...

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  3. A cell of emf 4V and internal resistance 0.5 is connected across a loa...

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  4. A battery gives a current of 0.5A with an external resistor of 12 Omeg...

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  5. battery gives a current of 0.5A with an external resistor of 12 Omega ...

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  6. A cell can be balanced against 110 cm and 100 cm of potentiometer wire...

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  7. A resistance wire connected in the left gap of a metre bridge balances...

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  8. In a potentiometer arrangement, a cell of emf 1.25 V gives a balance p...

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  9. With a certain cell, the balance point is obtained at 65 cm from the e...

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  10. Two wires of same metal have same length, but their cross sections are...

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  11. A wire of resistance R is cut into n equal parts. These parts are conn...

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  12. The resistance of a 10m long wire is 10 Omega. Its length is increased...

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  13. If there is an increase in length by 0.1% due to stretching the percen...

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  14. How many electrons constitute current of one ampere?

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  15. A car battery has emf 12V and internal resistance 5 x 10^-2 Omega. it ...

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  16. The internal resistance of a cell of emf 2V is 0.1Omega. It is connect...

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  17. The resistance in two gaps of a meter bridge are 10 Omega and 30 Omega...

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  18. What is a potentiometer? Why is it most accurate device in measuring e...

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  19. In a potentiometer experiment the balancing length with a cell is 560 ...

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  20. Two resistances are joined in parallel whose resultant is 6/5 ohms. On...

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