In a potentiometer arrangement, a cell of emf 1.25 V gives a balance point at 35.0 cm length of the wire. If the cell is replaced by another cell and the balance point shifts to 63.0 cm, what is the emf of the second cell?

In a potentiometer experiment, it is found that no current passes through the galvanometer, when the terminals of a cell are connected across 50 cm of the potentiometer wire. If the cell is shunted by a resistance of 5 ohm, the balance point is found at 40 cm of the wire from the same end. Find the internal resistance of the cell.

With a certain cell, the balance point is obtained at 65 cm from the end of apotentiometer wire. With another cell whose emf differs from that of the first by 0.1V the balance point is obtained at 60cm. Find the emf of each cell.

In a potentiometer experiment the balancing length with a cell is 560 cm. When an external resistance of 10 Omega is connected in parallel to the cell, the balancing length changes to 60 cm. The internal resistance of the cell is

Using a potentiometer, balance points are obtained at 60 cm and 10 cm with two cells connected in series first to support one another and then in opposition respectively. Find the ratio of the emfs of the cells.

In a meterbridge length of the wire is 100cm. At what point balance point be obtained if the resistance are in the ratio 4:5.

A potentiometer wire is of length 10 m and has a total resistance of 18 ohm. It carries a current of 120 mA. What length of it will be necessary to balance a cell of emf 1.5 volt ?