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A={2,3,5,7,11,...89,97} B={4,6,8,10,12,...

A={2,3,5,7,11,...89,97}
B={4,6,8,10,12,...98,100}
C={1,9,15,21,25,27,33...95,99}
The average of all the elements of A,B and C is :

A

49.5

B

50.5

C

55

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the average of all the elements in the sets A, B, and C, we will follow these steps: ### Step 1: Identify the elements in each set - Set A consists of all prime numbers between 1 and 100. - Set B consists of all even numbers between 1 and 100. - Set C consists of specific odd numbers between 1 and 100. ### Step 2: Determine the total number of elements in each set - **Set A (Prime Numbers)**: The prime numbers between 1 and 100 are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97. There are 25 prime numbers in total. - **Set B (Even Numbers)**: The even numbers between 1 and 100 are: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90, 92, 94, 96, 98, 100. There are 50 even numbers in total. - **Set C (Specific Odd Numbers)**: The odd numbers in set C are: 1, 9, 15, 21, 25, 27, 33, 35, 39, 45, 49, 51, 55, 57, 63, 65, 69, 75, 81, 83, 87, 91, 93, 95, 99. There are 25 specific odd numbers in total. ### Step 3: Calculate the total number of elements in all sets - Total elements = Number of elements in A + Number of elements in B + Number of elements in C - Total elements = 25 + 50 + 25 = 100 ### Step 4: Calculate the sum of all elements in each set - **Sum of Set A**: The sum of the prime numbers from 1 to 100 is 1060. - **Sum of Set B**: The sum of the first 50 even numbers can be calculated using the formula for the sum of an arithmetic series: \[ \text{Sum} = n/2 \times (\text{first term} + \text{last term}) = 50/2 \times (2 + 100) = 25 \times 102 = 2550 \] - **Sum of Set C**: The sum of the specific odd numbers can be calculated directly: \[ 1 + 9 + 15 + 21 + 25 + 27 + 33 + 35 + 39 + 45 + 49 + 51 + 55 + 57 + 63 + 65 + 69 + 75 + 81 + 83 + 87 + 91 + 93 + 95 + 99 = 1225 \] ### Step 5: Calculate the total sum of all elements - Total sum = Sum of A + Sum of B + Sum of C - Total sum = 1060 + 2550 + 1225 = 4835 ### Step 6: Calculate the average - Average = Total sum / Total number of elements - Average = 4835 / 100 = 48.35 ### Final Answer The average of all the elements of A, B, and C is **48.35**. ---
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A={2,3,5,7,11,...89,97} B={4,6,8,10,12,...98,100} C={1,9,15,21,25,27,33...95,99} The average of all the elements of B is :

There are 3 sets of natural numbers 1 ot 100. Set A contains all the natural numbers which are prime, upto 100. Set B contains all the non-prime even natural numbers upto 100. Set C contains all the non-prime odd natural numbers upto 100 i.e., A = {2,3,5,7,11,...89, 97} B = {4,6,8,10,12,...98,100} C = {1,9,15,21,25,27,33,95,99} The average of all the elements of B is :

A={2,3,5,7,11,...89,97} B={4,6,8,10,12,...98,100} C={3,9,15,21,27,33...,99} The average of all the perfect squares of the Set C is :

A={2,3,5,7,11,...89,97} B={4,6,8,10,12,...98,100} C={1,9,15,21,25,27,33...95,99} Any 10 elements of Set A are transferred to the Set B,then the average of Set B :

A={2,3,5,7,11,...89,97} B={4,6,8,10,12,...98,100} C={3,9,15,21,27,33...,99} If a smallest and a greatest element of the Set B is transferred to Set A, then the average of A,B,C respectively :

A={2,3,5,7,11,...89,97} B={4,6,8,10,12,...98,100} C={3,9,15,21,27,33...,99} If a least and a greatest element of Set C are transferred from Set C to Set A then the average of Set A :

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