The population of a town was 1,60,000 three years ago, If it increased by 3%, 2.5% and 5% respectively in the last three years, then the present population is

Options

A. A) 155679
B. B) 167890
C. B) 167890
D. D) 177366

Answer

To solve the problem step by step, we will calculate the present population of the town after three years of growth at the specified rates.

### Step-by-Step Solution:

1. **Initial Population**:
The population of the town three years ago was 160,000.

2. **First Year Increase**:
The population increased by 3% in the first year.
- To calculate the increase:
\[ \text{Increase} = 160,000 \times \frac{3}{100} = 4,800 \]
- New population after the first year:
\[ \text{Population after Year 1} = 160,000 + 4,800 = 164,800 \]

3. **Second Year Increase**:
The population increased by 2.5% in the second year.
- To calculate the increase:
\[ \text{Increase} = 164,800 \times \frac{2.5}{100} = 4,120 \]
- New population after the second year:
\[ \text{Population after Year 2} = 164,800 + 4,120 = 168,920 \]

4. **Third Year Increase**:
The population increased by 5% in the third year.
- To calculate the increase:
\[ \text{Increase} = 168,920 \times \frac{5}{100} = 8,446 \]
- New population after the third year:
\[ \text{Population after Year 3} = 168,920 + 8,446 = 177,366 \]

5. **Present Population**:
The present population of the town after three years is 177,366.

### Final Answer:
The present population of the town is **177,366**.

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