A milkman has two types of milk. In the first container the percentage of milk is 80% and in the second container the percentage of milk is 60%. If he mixes 28 liters of milk of the first container to the 32 liters of milk of the second container, then percentage of milk in the mixture is :

Options

A. 69.99
B. 69.33
C. 72.5
D. 75.2

Explanation

To solve the problem, we need to find the percentage of milk in the mixture after mixing 28 liters of milk from the first container (80% milk) and 32 liters from the second container (60% milk).

### Step-by-Step Solution:

1. **Calculate the amount of milk in the first container:**
- The first container has 80% milk.
- Amount of milk in 28 liters from the first container = 80% of 28 liters.
- Calculation:
\[ \text{Milk from first container} = 0.80 \times 28 = 22.4 \text{ liters} \]

2. **Calculate the amount of milk in the second container:**
- The second container has 60% milk.
- Amount of milk in 32 liters from the second container = 60% of 32 liters.
- Calculation:
\[ \text{Milk from second container} = 0.60 \times 32 = 19.2 \text{ liters} \]

3. **Calculate the total amount of milk in the mixture:**
- Total milk = Milk from first container + Milk from second container.
- Calculation:
\[ \text{Total milk} = 22.4 + 19.2 = 41.6 \text{ liters} \]

4. **Calculate the total volume of the mixture:**
- Total volume = Volume from first container + Volume from second container.
- Calculation:
\[ \text{Total volume} = 28 + 32 = 60 \text{ liters} \]

5. **Calculate the percentage of milk in the mixture:**
- Percentage of milk = (Total milk / Total volume) × 100.
- Calculation:
\[ \text{Percentage of milk} = \left( \frac{41.6}{60} \right) \times 100 = 69.33\% \]

### Final Answer:
The percentage of milk in the mixture is **69.33%**.