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In a 50 litre mixture of water and milk,...

In a 50 litre mixture of water and milk, water is only `20%.` The milkman gives 10 liters of this mixture to a customer and then he adds up 10 liters of pure water in the remaining mixture. The percenatge of water in the final mixture is :

A

`84%`

B

`74%`

C

`26%`

D

`36%`

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The correct Answer is:
To solve the problem step by step, let's break it down: ### Step 1: Determine the initial amount of water and milk in the mixture. - The total volume of the mixture is 50 liters. - Water constitutes 20% of the mixture. \[ \text{Amount of water} = 20\% \text{ of } 50 \text{ liters} = \frac{20}{100} \times 50 = 10 \text{ liters} \] - Therefore, the amount of milk in the mixture is: \[ \text{Amount of milk} = 50 \text{ liters} - 10 \text{ liters} = 40 \text{ liters} \] ### Step 2: Calculate the remaining mixture after giving 10 liters to the customer. - The milkman gives away 10 liters of the mixture. Thus, the remaining mixture is: \[ \text{Remaining mixture} = 50 \text{ liters} - 10 \text{ liters} = 40 \text{ liters} \] ### Step 3: Determine the amount of water and milk in the remaining 40 liters. - Since the mixture is uniform, the ratio of water and milk remains the same in the 10 liters given away. - The amount of water in the 10 liters given away is: \[ \text{Water in 10 liters} = 20\% \text{ of } 10 \text{ liters} = \frac{20}{100} \times 10 = 2 \text{ liters} \] - Therefore, the amount of water left in the remaining 40 liters is: \[ \text{Remaining water} = 10 \text{ liters} - 2 \text{ liters} = 8 \text{ liters} \] - The amount of milk left in the remaining 40 liters is: \[ \text{Remaining milk} = 40 \text{ liters} - 8 \text{ liters} = 32 \text{ liters} \] ### Step 4: Add 10 liters of pure water to the remaining mixture. - After giving away the mixture, the milkman adds 10 liters of pure water to the remaining mixture. - Thus, the total amount of water after adding the pure water is: \[ \text{Total water} = 8 \text{ liters} + 10 \text{ liters} = 18 \text{ liters} \] ### Step 5: Calculate the total volume of the final mixture. - The total volume of the final mixture is: \[ \text{Total final mixture} = 40 \text{ liters} + 10 \text{ liters} = 50 \text{ liters} \] ### Step 6: Calculate the percentage of water in the final mixture. - The percentage of water in the final mixture is calculated as follows: \[ \text{Percentage of water} = \left( \frac{\text{Total water}}{\text{Total final mixture}} \right) \times 100 = \left( \frac{18 \text{ liters}}{50 \text{ liters}} \right) \times 100 = 36\% \] ### Final Answer: The percentage of water in the final mixture is **36%**. ---
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