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A butler stole wine from a butt of sherr...

A butler stole wine from a butt of sherry containing `50%` of spirit, then he replenished it by different wine containing `20%` spirit. Thus there was only `30%` strength (spirit) in the new mixture. How much of the original wine did he steal?

A

44256

B

44257

C

44228

D

44287

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we will use the method of alligation. Here's a step-by-step breakdown of the solution: ### Step 1: Identify the strengths of the wines involved - The original wine has a spirit strength of 50%. - The wine used to replenish has a spirit strength of 20%. - The resulting mixture has a spirit strength of 30%. ### Step 2: Set up the alligation We will set up the alligation to find the ratio of the quantities of the two wines. - The formula for alligation is: \[ \text{Difference between the strengths} = \text{Strength of one wine} - \text{Strength of mixture} \] \[ \text{Difference between the strengths} = \text{Strength of mixture} - \text{Strength of other wine} \] ### Step 3: Calculate the differences - For the 50% wine: \[ 50\% - 30\% = 20\% \] - For the 20% wine: \[ 30\% - 20\% = 10\% \] ### Step 4: Set up the ratio Now we can set up the ratio of the quantities of the two wines: \[ \text{Ratio} = \frac{20}{10} = 2:1 \] This means that for every 2 parts of the original wine (50% spirit), there is 1 part of the replenishing wine (20% spirit). ### Step 5: Determine the total parts The total parts in the mixture is: \[ 2 + 1 = 3 \text{ parts} \] ### Step 6: Calculate the proportion of the original wine The proportion of the original wine in the mixture is: \[ \frac{2 \text{ parts}}{3 \text{ parts}} = \frac{2}{3} \] ### Step 7: Conclusion Thus, the butler stole \(\frac{2}{3}\) of the original wine. ---
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