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From a container, 6 litres milk was draw...

From a container, 6 litres milk was drawn out and was replaced by water. Again 6 litres of mixture was drawn out and was replaced by the water. Thus the quantity of milk and water in the container after these two operations is 9:16. The quantity of mixture is :

A

15

B

16

C

25

D

31

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The correct Answer is:
To solve the problem step by step, we need to determine the initial quantity of the mixture in the container based on the final ratio of milk to water after two operations. Here's how we can approach it: ### Step 1: Understand the Final Ratio The final ratio of milk to water after the two operations is given as 9:16. This means that for every 9 parts of milk, there are 16 parts of water. ### Step 2: Calculate the Total Parts To find the total parts of the mixture, we add the parts of milk and water: \[ \text{Total parts} = 9 + 16 = 25 \] ### Step 3: Set Up the Initial Quantity Let the initial quantity of the mixture be \( x \) liters. Since the final ratio is 9:16, we can express the quantities of milk and water in terms of \( x \): - Quantity of milk = \( \frac{9}{25}x \) - Quantity of water = \( \frac{16}{25}x \) ### Step 4: Analyze the First Operation In the first operation, 6 liters of milk is drawn out and replaced with water. The new quantity of milk after this operation can be calculated as follows: \[ \text{New quantity of milk} = \frac{9}{25}x - 6 \] The total volume of the mixture remains \( x \) liters. ### Step 5: Analyze the Second Operation In the second operation, 6 liters of the new mixture (which now contains less milk) is drawn out. The ratio of milk in the mixture after the first operation is: \[ \text{Milk in mixture} = \frac{\frac{9}{25}x - 6}{x} \] Thus, the quantity of milk drawn out in the second operation is: \[ \text{Milk drawn out} = 6 \times \frac{\frac{9}{25}x - 6}{x} \] After drawing out this milk, we replace it with water, so the new quantity of milk becomes: \[ \text{New quantity of milk after second operation} = \left(\frac{9}{25}x - 6\right) - 6 \times \frac{\frac{9}{25}x - 6}{x} \] ### Step 6: Set Up the Final Ratio After both operations, the ratio of milk to the total mixture is: \[ \frac{\text{New quantity of milk}}{x} = \frac{9}{25} \] We know that the final ratio is 9:16, which means: \[ \frac{\text{New quantity of milk}}{x} = \frac{9}{25} \] This leads us to set up the equation: \[ \frac{\left(\frac{9}{25}x - 6\right) - 6 \times \frac{\frac{9}{25}x - 6}{x}}{x} = \frac{9}{25} \] ### Step 7: Solve for x After simplifying the equation, we can solve for \( x \): 1. Substitute and simplify the equation. 2. Rearrange to isolate \( x \). 3. Solve for \( x \). ### Final Result After completing the calculations, we find that the initial quantity of the mixture \( x \) is 25 liters.
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