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If (x+y)/(x-y)=5/3 and x/(y+2)=2, then t...

If `(x+y)/(x-y)=5/3` and `x/(y+2)=2`, then the value of (x,y) is

A

(4,1)

B

(2,8)

C

(1,4)

D

(8,2)

Text Solution

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The correct Answer is:
To solve the equations given in the problem, we will follow these steps: ### Step 1: Start with the first equation We have the equation: \[ \frac{x+y}{x-y} = \frac{5}{3} \] Cross-multiply to eliminate the fraction: \[ 3(x+y) = 5(x-y) \] ### Step 2: Expand both sides Expanding both sides gives: \[ 3x + 3y = 5x - 5y \] ### Step 3: Rearrange the equation Rearranging the equation to group like terms: \[ 3x + 3y - 5x + 5y = 0 \] This simplifies to: \[ -2x + 8y = 0 \] or \[ 2x = 8y \] Dividing both sides by 2: \[ x = 4y \] ### Step 4: Substitute into the second equation Now we use the second equation: \[ \frac{x}{y+2} = 2 \] Substituting \(x = 4y\) into this equation: \[ \frac{4y}{y+2} = 2 \] ### Step 5: Cross-multiply again Cross-multiplying gives: \[ 4y = 2(y + 2) \] ### Step 6: Expand and simplify Expanding the right side: \[ 4y = 2y + 4 \] Rearranging gives: \[ 4y - 2y = 4 \] This simplifies to: \[ 2y = 4 \] Dividing both sides by 2: \[ y = 2 \] ### Step 7: Find the value of x Now substituting \(y = 2\) back into \(x = 4y\): \[ x = 4(2) = 8 \] ### Final Result Thus, the values of \(x\) and \(y\) are: \[ (x, y) = (8, 2) \] ---
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