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A and B are two alloys of copper and tin...

A and B are two alloys of copper and tin prepared by mixing the respective metals in the ratio of 5 : 3 and 5 : 11 respectively. If the alloys A and B are mixed to from a third alloy C with an equal proportion of copper and tin, what is the ratio of alloys A and B in the new alloy C?

A

3:5

B

4:5

C

3:2

D

2:3

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The correct Answer is:
To solve the problem, we need to determine the ratio of alloys A and B when mixed to form a new alloy C that has an equal proportion of copper and tin. Let's break this down step by step. ### Step 1: Understand the Composition of Alloys A and B - **Alloy A** is made of copper and tin in the ratio of 5:3. - Total parts = 5 + 3 = 8 - Copper in A = \( \frac{5}{8} \) - Tin in A = \( \frac{3}{8} \) - **Alloy B** is made of copper and tin in the ratio of 5:11. - Total parts = 5 + 11 = 16 - Copper in B = \( \frac{5}{16} \) - Tin in B = \( \frac{11}{16} \) ### Step 2: Determine the Composition of Alloy C Alloy C is required to have an equal proportion of copper and tin, which means: - Copper in C = Tin in C = \( \frac{1}{2} \) ### Step 3: Set Up the Allegation Method We can use the allegation method to find the ratio in which alloys A and B must be mixed to achieve the desired composition in alloy C. 1. **Calculate the difference between the copper proportions:** - Copper in A = \( \frac{5}{8} = 0.625 \) - Copper in B = \( \frac{5}{16} = 0.3125 \) - Copper in C = \( 0.5 \) Using the allegation method: - Difference between A and C: \( 0.625 - 0.5 = 0.125 \) - Difference between B and C: \( 0.5 - 0.3125 = 0.1875 \) 2. **Set up the ratio using the differences:** - The ratio of A to B is given by the differences calculated: - Ratio of A to B = \( 0.1875 : 0.125 \) ### Step 4: Simplify the Ratio To simplify the ratio: - Convert the decimals to fractions: - \( 0.1875 = \frac{3}{16} \) - \( 0.125 = \frac{1}{8} \) Now, we can express the ratio: - Ratio of A to B = \( \frac{3/16}{1/8} = \frac{3}{16} \times \frac{8}{1} = \frac{3 \times 8}{16} = \frac{24}{16} = \frac{3}{2} \) ### Final Ratio Thus, the ratio of alloys A and B in the new alloy C is **3:2**. ---
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