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Find the value of p if (14p-4): (8p-1)...

Find the value of p if
(14p-4): (8p-1) = (3p+8): (9p+5) -

A

1

B

0.5

C

0.75

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \( p \) in the equation \[ (14p - 4) : (8p - 1) = (3p + 8) : (9p + 5), \] we can set up a proportion and solve for \( p \). ### Step 1: Set up the equation We can write the proportion as: \[ \frac{14p - 4}{8p - 1} = \frac{3p + 8}{9p + 5}. \] ### Step 2: Cross-multiply Cross-multiplying gives us: \[ (14p - 4)(9p + 5) = (3p + 8)(8p - 1). \] ### Step 3: Expand both sides Now we will expand both sides of the equation. **Left Side:** \[ 14p \cdot 9p + 14p \cdot 5 - 4 \cdot 9p - 4 \cdot 5 = 126p^2 + 70p - 36p - 20 = 126p^2 + 34p - 20. \] **Right Side:** \[ 3p \cdot 8p + 3p \cdot (-1) + 8 \cdot 8p + 8 \cdot (-1) = 24p^2 - 3p + 64p - 8 = 24p^2 + 61p - 8. \] ### Step 4: Set the equation to zero Now we set the two sides equal to each other: \[ 126p^2 + 34p - 20 = 24p^2 + 61p - 8. \] Subtract \( 24p^2 + 61p - 8 \) from both sides: \[ 126p^2 - 24p^2 + 34p - 61p - 20 + 8 = 0. \] This simplifies to: \[ 102p^2 - 27p - 12 = 0. \] ### Step 5: Factor or use the quadratic formula To solve for \( p \), we can use the quadratic formula: \[ p = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, \] where \( a = 102 \), \( b = -27 \), and \( c = -12 \). ### Step 6: Calculate the discriminant First, we calculate the discriminant: \[ b^2 - 4ac = (-27)^2 - 4 \cdot 102 \cdot (-12). \] \[ = 729 + 4896 = 5625. \] ### Step 7: Substitute into the quadratic formula Now substitute back into the formula: \[ p = \frac{27 \pm \sqrt{5625}}{2 \cdot 102}. \] Since \( \sqrt{5625} = 75 \): \[ p = \frac{27 \pm 75}{204}. \] ### Step 8: Calculate the two possible values for \( p \) Calculating the two values: 1. \( p = \frac{27 + 75}{204} = \frac{102}{204} = \frac{1}{2} \). 2. \( p = \frac{27 - 75}{204} = \frac{-48}{204} = \frac{-16}{68} = \frac{-4}{17} \). ### Step 9: Conclusion Since \( p \) must be a positive value in this context, we take: \[ p = \frac{1}{2}. \]
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