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A retailer uses faulty balances to purch...

A retailer uses faulty balances to purchase and sell the goods. He uses his faulty balances in such a way that while buying the goods from wholesaler he gets `20%` more of what he pays for, while selling his goods to his customer he gives `10%` less of what he charges for. If he earns a profit of `60%` by how much per cent does he mark up his goods?

A

40

B

44.44

C

20

D

56.67

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the retailer's buying and selling process, calculate the effective cost price, selling price, and the markup percentage. ### Step-by-Step Solution: 1. **Understanding the Buying Process:** - When the retailer pays for 100 grams of goods, he actually receives 20% more due to the faulty balance. - Therefore, if he pays for 100 grams, he actually receives: \[ \text{Received Quantity} = 100 \text{ grams} + 20\% \text{ of } 100 \text{ grams} = 100 + 20 = 120 \text{ grams} \] 2. **Cost Price Calculation:** - Let’s assume the cost price for 100 grams is `100` rupees. - Thus, the cost price per gram is: \[ \text{Cost Price per gram} = \frac{100 \text{ rupees}}{100 \text{ grams}} = 1 \text{ rupee/gram} \] - The total cost for the 120 grams he actually receives is still `100` rupees. 3. **Understanding the Selling Process:** - When selling, the retailer charges for 100 grams but gives 10% less. - Therefore, when he charges for 100 grams, he actually sells: \[ \text{Sold Quantity} = 100 \text{ grams} - 10\% \text{ of } 100 \text{ grams} = 100 - 10 = 90 \text{ grams} \] 4. **Selling Price Calculation:** - Let’s assume he sells the 100 grams for `x` rupees. - The selling price for 90 grams is `x` rupees, which means the selling price per gram is: \[ \text{Selling Price per gram} = \frac{x \text{ rupees}}{90 \text{ grams}} \] 5. **Profit Calculation:** - The retailer earns a profit of `60%` on his cost price. - Therefore, the selling price can also be expressed as: \[ \text{Selling Price} = \text{Cost Price} + 60\% \text{ of Cost Price} = 100 + 60\% \text{ of } 100 = 100 + 60 = 160 \text{ rupees} \] 6. **Finding the Selling Price per Gram:** - Since he sells 90 grams for 160 rupees: \[ \text{Selling Price per gram} = \frac{160 \text{ rupees}}{90 \text{ grams}} \approx 1.78 \text{ rupees/gram} \] 7. **Markup Calculation:** - The markup is calculated based on the cost price. The formula for markup percentage is: \[ \text{Markup Percentage} = \left( \frac{\text{Selling Price} - \text{Cost Price}}{\text{Cost Price}} \right) \times 100 \] - Plugging in the values: \[ \text{Markup Percentage} = \left( \frac{160 - 100}{100} \right) \times 100 = \left( \frac{60}{100} \right) \times 100 = 60\% \] ### Conclusion: The retailer marks up his goods by `60%`.
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