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A certain sum amounts to ₹ 8988.8 in two...

A certain sum amounts to ₹ 8988.8 in two years and to ₹ 9528.128 in three years, at compound interest per annum. What is the principal and rate of interest?

A

`₹1200,5%`

B

`₹ 6,00,8%`

C

`₹ 8,000,6%`

D

`₹ 10,000,8.5%`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the principal amount (P) and the rate of interest (R) given the amounts after 2 years and 3 years at compound interest. ### Step 1: Understand the relationship between amounts Let: - A1 = Amount after 2 years = ₹ 8988.8 - A2 = Amount after 3 years = ₹ 9528.128 The relationship between the amounts can be expressed as: \[ A2 = A1 \times (1 + R) \] ### Step 2: Set up the equation From the relationship above, we can express the rate of interest (R) as: \[ 9528.128 = 8988.8 \times (1 + R) \] ### Step 3: Solve for (1 + R) Rearranging the equation gives: \[ 1 + R = \frac{9528.128}{8988.8} \] ### Step 4: Calculate (1 + R) Now, calculate the value: \[ 1 + R = \frac{9528.128}{8988.8} \approx 1.0596 \] ### Step 5: Find R Now, subtract 1 from both sides to find R: \[ R \approx 1.0596 - 1 = 0.0596 \] \[ R \approx 0.0596 \times 100 = 5.96\% \] ### Step 6: Use A1 to find the principal Now that we have R, we can find the principal amount using the formula for the amount after 2 years: \[ A1 = P \times (1 + R)^2 \] Substituting the known values: \[ 8988.8 = P \times (1.0596)^2 \] ### Step 7: Calculate (1 + R)^2 Calculating \( (1.0596)^2 \): \[ (1.0596)^2 \approx 1.1275 \] ### Step 8: Solve for P Now we can rearrange the equation to find P: \[ P = \frac{8988.8}{1.1275} \approx 7976.23 \] ### Final Results - Principal (P) = ₹ 7976.23 - Rate of Interest (R) = 5.96%
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