Home
Class 14
MATHS
Two persons having different productivit...

Two persons having different productivity of labour, working together can reap a field in 2 days. If one-third of the field was reaped by the first man and rest by the other one working alternatively took 4 days. How long did it take for the faster person to reap the whole field working alone?

A

12

B

8

C

6

D

3

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to break it down step by step. ### Step 1: Understand the total work done Let’s denote the total work required to reap the field as 1 unit of work. ### Step 2: Calculate the combined work rate of both persons Since both persons can reap the field together in 2 days, their combined work rate is: \[ \text{Combined work rate} = \frac{1 \text{ unit}}{2 \text{ days}} = \frac{1}{2} \text{ units per day} \] ### Step 3: Determine the work done by the first person According to the problem, the first person reaped one-third of the field: \[ \text{Work done by the first person} = \frac{1}{3} \text{ units} \] ### Step 4: Calculate the time taken by the first person to reap his share Let’s denote the time taken by the first person to reap his share as \( t_1 \). Since he works alone, we can express his work rate as \( r_1 \): \[ r_1 = \frac{1}{3} \text{ units} \text{ in } t_1 \text{ days} \] ### Step 5: Determine the work done by the second person The remaining work done by the second person is: \[ \text{Work done by the second person} = 1 - \frac{1}{3} = \frac{2}{3} \text{ units} \] ### Step 6: Calculate the time taken by the second person Let’s denote the time taken by the second person to reap his share as \( t_2 \). Since they worked alternatively for a total of 4 days, we can express this as: \[ t_1 + t_2 = 4 \text{ days} \] ### Step 7: Work rates of the two persons Let’s denote the work rates of the first and second persons as \( r_1 \) and \( r_2 \) respectively. From the combined work rate: \[ r_1 + r_2 = \frac{1}{2} \text{ units per day} \] ### Step 8: Express the work done by the second person Since the second person worked for \( t_2 \) days, we can express the work done by him as: \[ r_2 \cdot t_2 = \frac{2}{3} \text{ units} \] ### Step 9: Substitute \( t_2 \) in terms of \( t_1 \) From the equation \( t_1 + t_2 = 4 \), we can express \( t_2 \) as: \[ t_2 = 4 - t_1 \] ### Step 10: Substitute into the work equation Substituting \( t_2 \) into the work done by the second person: \[ r_2 \cdot (4 - t_1) = \frac{2}{3} \] ### Step 11: Solve for \( t_1 \) and \( t_2 \) Now we have two equations: 1. \( r_1 + r_2 = \frac{1}{2} \) 2. \( r_2 \cdot (4 - t_1) = \frac{2}{3} \) Using the first equation, we can express \( r_2 \) in terms of \( r_1 \): \[ r_2 = \frac{1}{2} - r_1 \] Substituting this into the second equation gives us: \[ \left(\frac{1}{2} - r_1\right)(4 - t_1) = \frac{2}{3} \] ### Step 12: Solve the equations to find individual work rates This will lead us to find the values of \( r_1 \) and \( r_2 \). Once we have \( r_2 \), we can find out how long it takes for the faster person to reap the whole field alone. ### Step 13: Calculate the time for the faster person Let’s assume the faster person is the second person (as he worked more). The time taken by the second person to reap the whole field alone is: \[ \text{Time} = \frac{1 \text{ unit}}{r_2} \] ### Final Step: Conclusion After solving the equations, we can find the exact time taken by the faster person to reap the whole field alone.
Promotional Banner

Topper's Solved these Questions

  • THEORY OF EQUATIONS

    QUANTUM CAT|Exercise QUESTION BANK|573 Videos
  • TIME, SPEED AND DISTANCE

    QUANTUM CAT|Exercise QUESTION BANK|368 Videos

Similar Questions

Explore conceptually related problems

42 workers can reap a field in 8 days. If the work is to be completed in 7 days, the extra workers needed are:

56 workers can reap a field in 8 days. If the work is to be completed in 7 days, the extra workers needed are:

If 30men working 18h per day can reap a field in 32 days, in how many days can 36 men reap the field working 16h per day ?

25 men can reap a field in 20 days. When should 15men leave the work, if the whole field is to be reaped in 35 days after they leave the work?

If 3 men or 4 women can reap a field in 43 days. How long will 7 men and 5 women take to reap it?

If 30 men working 9 h per day can reap a field in 16 days, in how many days, will 36 men reap the field working 8 h per day ?

16 persons can reap 1/5th field in 6 days. How many persons (with same efficiency) are required to reap rest of the field in 8 days?

QUANTUM CAT-TIME AND WORK-QUESTION BANK
  1. Eklavya can do the 6 times the actual work in 36 days while Faizal can...

    Text Solution

    |

  2. Progressive Company Pvt. Ltd. hired some employees in a fix pattern. O...

    Text Solution

    |

  3. Two persons having different productivity of labour, working together ...

    Text Solution

    |

  4. The total number of men, women and children working in a factory is 18...

    Text Solution

    |

  5. A group of workers was put on a job. From the second day onwards, one...

    Text Solution

    |

  6. Two workers undertake to do a job. The second-worker started working 2...

    Text Solution

    |

  7. A group of men deaded to do a job in 4 days. But since 20 men dropped ...

    Text Solution

    |

  8. Brahma, Vishnu and Mahesh are three friends with different productivit...

    Text Solution

    |

  9. Milinda takes 8 1/3 hours more when she works alone in comparison of w...

    Text Solution

    |

  10. Pascal and Rascal are two workers. Working together they can complete ...

    Text Solution

    |

  11. Boston, Churchill and David are three workers, employed by a contracto...

    Text Solution

    |

  12. There are three boats B1, B2 and B3 working together they carry 60 peo...

    Text Solution

    |

  13. Three men and 5 women together can finish a job in 3 days. Working on ...

    Text Solution

    |

  14. Henry and Ford are two different persons, but when they work together,...

    Text Solution

    |

  15. Anne, Benne and Cenne are three friends. Anne and Benne are twins. Ben...

    Text Solution

    |

  16. Three typists A, B and C working together 8 hours per a can type 900 p...

    Text Solution

    |

  17. Pipes A,B and C can fill a tank in 15, 20 and 30 hours respectively Th...

    Text Solution

    |

  18. Four pipe A, B, C and D can fill a cistern in 20, 25, 40 and 50 hours ...

    Text Solution

    |

  19. A tank is connected with four pipes A, B, C and D of which two are fil...

    Text Solution

    |

  20. Two pipes A and B can fill a tank in 24 hours and (120)/7 hours respec...

    Text Solution

    |