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A train of length 100 m takes 1/6 minute...

A train of length 100 m takes 1/6 minute to pass over another train 150 m long coming from the opposite direction if the speed of first train is 60 km/h the speed of the second train is:

A

45 km/h

B

28 km/h

C

30 km/h

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow these steps: ### Step 1: Understand the problem We have two trains: - Train A (length = 100 m, speed = 60 km/h) - Train B (length = 150 m, speed = x km/h) Train A takes 1/6 minutes to completely pass Train B. ### Step 2: Convert time from minutes to seconds Since the time given is in minutes, we need to convert it into seconds for easier calculations. \[ \text{Time} = \frac{1}{6} \text{ minutes} = \frac{1}{6} \times 60 \text{ seconds} = 10 \text{ seconds} \] ### Step 3: Calculate the total distance covered while passing When two trains pass each other, the total distance covered is the sum of their lengths: \[ \text{Total Distance} = \text{Length of Train A} + \text{Length of Train B} = 100 \text{ m} + 150 \text{ m} = 250 \text{ m} \] ### Step 4: Determine the relative speed of the trains Since the trains are moving towards each other, their relative speed is the sum of their speeds: \[ \text{Relative Speed} = \text{Speed of Train A} + \text{Speed of Train B} = 60 \text{ km/h} + x \text{ km/h} \] ### Step 5: Convert the relative speed from km/h to m/s To convert km/h to m/s, we use the conversion factor \( \frac{5}{18} \): \[ \text{Relative Speed in m/s} = \left(60 + x\right) \times \frac{5}{18} \text{ m/s} \] ### Step 6: Use the formula for distance Using the formula for distance (Distance = Speed × Time), we can set up the equation: \[ 250 = \left(60 + x\right) \times \frac{5}{18} \times 10 \] ### Step 7: Simplify the equation First, simplify the right side: \[ 250 = \left(60 + x\right) \times \frac{50}{18} \] Now, multiply both sides by 18 to eliminate the fraction: \[ 250 \times 18 = (60 + x) \times 50 \] \[ 4500 = (60 + x) \times 50 \] ### Step 8: Divide both sides by 50 \[ \frac{4500}{50} = 60 + x \] \[ 90 = 60 + x \] ### Step 9: Solve for x Subtract 60 from both sides: \[ x = 90 - 60 \] \[ x = 30 \text{ km/h} \] ### Final Answer The speed of the second train is **30 km/h**.
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