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A girl while walking diametrically acros...

A girl while walking diametrically across a semicircular playground takes 3 minutes less than if she had kept walking round the circular path from A to B If she walks 60 metres a minute, what is the diameter of the play ground

A

60 m

B

48 m

C

84 m

D

315 m

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the diameter of the semicircular playground based on the information given. Let's break it down step by step. ### Step 1: Define the Variables Let the diameter of the semicircular playground be \( D \) meters. The radius \( R \) will then be \( \frac{D}{2} \). ### Step 2: Calculate the Distance for Each Path 1. **Distance across the semicircle (diametrically)**: The distance when walking across the semicircle is equal to the diameter, which is \( D \) meters. 2. **Distance around the semicircle**: The circumference of a full circle is given by \( \pi D \). Therefore, the distance around the semicircle (which is half the circumference) is \( \frac{\pi D}{2} \) meters. ### Step 3: Calculate the Time Taken for Each Path 1. **Time taken to walk across the semicircle**: \[ \text{Time across} = \frac{D}{60} \text{ minutes} \] 2. **Time taken to walk around the semicircle**: \[ \text{Time around} = \frac{\frac{\pi D}{2}}{60} = \frac{\pi D}{120} \text{ minutes} \] ### Step 4: Set Up the Equation According to the problem, the time taken to walk across the semicircle is 3 minutes less than the time taken to walk around it. Therefore, we can set up the equation: \[ \frac{D}{60} = \frac{\pi D}{120} - 3 \] ### Step 5: Solve the Equation 1. Multiply through by 120 to eliminate the denominators: \[ 2D = \pi D - 360 \] 2. Rearranging gives: \[ \pi D - 2D = 360 \] \[ D(\pi - 2) = 360 \] 3. Finally, solve for \( D \): \[ D = \frac{360}{\pi - 2} \] ### Step 6: Calculate the Diameter Using the approximate value of \( \pi \approx 3.14 \): \[ D \approx \frac{360}{3.14 - 2} = \frac{360}{1.14} \approx 315.79 \text{ meters} \] ### Conclusion The diameter of the playground is approximately \( 315.79 \) meters. ---
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