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Reaction in which one of the products is...

Reaction in which one of the products is water.

A

precipitation reaction

B

decomposition reaction

C

neutralizaion reaction

D

single displacement reaction

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The correct Answer is:
It seems that the provided video transcript does not relate to the chemistry question regarding reactions that produce water. However, I can still provide a step-by-step text solution for the question "What is a reaction in which one of the products is water?" ### Step-by-Step Solution: 1. **Understanding Chemical Reactions**: - A chemical reaction involves the transformation of reactants into products. In some reactions, one of the products formed is water (H₂O). 2. **Identifying Types of Reactions**: - There are several types of chemical reactions, but one common type that produces water is a **combination reaction** or **synthesis reaction**. 3. **Example of a Reaction Producing Water**: - A classic example of a reaction that produces water is the combustion of hydrocarbons. For instance, when methane (CH₄) combusts in the presence of oxygen (O₂), the products are carbon dioxide (CO₂) and water (H₂O). - The balanced chemical equation for this reaction is: \[ CH₄ + 2O₂ \rightarrow CO₂ + 2H₂O \] 4. **Acid-Base Neutralization**: - Another example is an **acid-base neutralization reaction**. When an acid reacts with a base, water is formed along with a salt. For example, when hydrochloric acid (HCl) reacts with sodium hydroxide (NaOH), the products are sodium chloride (NaCl) and water (H₂O). - The balanced chemical equation is: \[ HCl + NaOH \rightarrow NaCl + H₂O \] 5. **Conclusion**: - In summary, reactions that produce water include combustion reactions and acid-base neutralization reactions. These reactions are fundamental in chemistry and illustrate the formation of water as a product.
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Knowledge Check

  • Which of the following reaction will lead to the reaction of two chiral centres in the product ?

    A
    `CH_(3)CH=CHCH_(3)+Br_(2)overset(C Cl_(4))rarr`
    B
    `CH_(3)CH_(2)CH=CH_(2)+Br_(2)overset(C Cl_(4))rarr`
    C
    `CH_(3)CH=CHCH_(3)+HBrrarr`
    D
    `CH_(3)CH_(2)CH=CH_(2)+HBrrarr`
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