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If sin x = 3/(5), then cos x is...

If `sin x = 3/(5)`, then cos x is

A

`4/(5)` but not `-4/(5)`

B

`4/(5)` or `-4/(5)`

C

`-4/(5)` but not `4/(5)`

D

none of these

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The correct Answer is:
To find the value of \( \cos x \) given that \( \sin x = \frac{3}{5} \), we can use the Pythagorean identity: \[ \sin^2 x + \cos^2 x = 1 \] ### Step-by-Step Solution: 1. **Start with the Pythagorean Identity**: \[ \sin^2 x + \cos^2 x = 1 \] 2. **Substitute the value of \( \sin x \)**: Since \( \sin x = \frac{3}{5} \), we find \( \sin^2 x \): \[ \sin^2 x = \left(\frac{3}{5}\right)^2 = \frac{9}{25} \] 3. **Substitute \( \sin^2 x \) into the identity**: \[ \frac{9}{25} + \cos^2 x = 1 \] 4. **Isolate \( \cos^2 x \)**: \[ \cos^2 x = 1 - \frac{9}{25} \] 5. **Convert 1 to a fraction with a denominator of 25**: \[ 1 = \frac{25}{25} \] So, \[ \cos^2 x = \frac{25}{25} - \frac{9}{25} = \frac{16}{25} \] 6. **Take the square root to find \( \cos x \)**: \[ \cos x = \sqrt{\frac{16}{25}} = \frac{4}{5} \] 7. **Consider the sign of \( \cos x \)**: Since we are not given the quadrant in which \( x \) lies, we typically take the positive root unless specified otherwise. Thus, \[ \cos x = \frac{4}{5} \] ### Final Answer: \[ \cos x = \frac{4}{5} \]
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