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If sinx=1/(3), then the value of sin3x i...

If `sinx=1/(3)`, then the value of `sin3x` is

A

1

B

0

C

`23/(27)`

D

`-23/(27)`

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The correct Answer is:
To find the value of \( \sin 3x \) given that \( \sin x = \frac{1}{3} \), we can use the formula for \( \sin 3\theta \): \[ \sin 3\theta = 3\sin \theta - 4\sin^3 \theta \] ### Step 1: Substitute \( \sin x \) into the formula Let \( \theta = x \). Then we have: \[ \sin 3x = 3\sin x - 4\sin^3 x \] Substituting \( \sin x = \frac{1}{3} \): \[ \sin 3x = 3\left(\frac{1}{3}\right) - 4\left(\frac{1}{3}\right)^3 \] ### Step 2: Simplify the expression Calculating \( 3\left(\frac{1}{3}\right) \): \[ 3\left(\frac{1}{3}\right) = 1 \] Now, calculate \( \left(\frac{1}{3}\right)^3 \): \[ \left(\frac{1}{3}\right)^3 = \frac{1}{27} \] Now substitute this back into the equation: \[ \sin 3x = 1 - 4\left(\frac{1}{27}\right) \] ### Step 3: Calculate \( 4\left(\frac{1}{27}\right) \) Calculating \( 4\left(\frac{1}{27}\right) \): \[ 4\left(\frac{1}{27}\right) = \frac{4}{27} \] ### Step 4: Final calculation Now substitute this back into the equation for \( \sin 3x \): \[ \sin 3x = 1 - \frac{4}{27} \] To perform the subtraction, we need a common denominator: \[ 1 = \frac{27}{27} \] Thus, \[ \sin 3x = \frac{27}{27} - \frac{4}{27} = \frac{27 - 4}{27} = \frac{23}{27} \] ### Final Answer The value of \( \sin 3x \) is: \[ \sin 3x = \frac{23}{27} \] ---
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