Home
Class 11
MATHS
If for a distribution sumx(i)^2=2400 and...

If for a distribution `sumx_(i)^2=2400` and `sumx_(i)=250` and the total number of observations is 50, then variance is

A

(a) 20

B

(b) 21

C

(c) 22

D

(d) 23

Text Solution

AI Generated Solution

The correct Answer is:
To find the variance of the given distribution, we will use the formula for variance: \[ \sigma^2 = \frac{\sum x_i^2}{N} - \left(\frac{\sum x_i}{N}\right)^2 \] Where: - \(\sigma^2\) is the variance, - \(\sum x_i^2\) is the sum of the squares of the observations, - \(\sum x_i\) is the sum of the observations, - \(N\) is the total number of observations. Given: - \(\sum x_i^2 = 2400\) - \(\sum x_i = 250\) - \(N = 50\) Now, let's calculate the variance step by step: ### Step 1: Calculate \(\frac{\sum x_i^2}{N}\) \[ \frac{\sum x_i^2}{N} = \frac{2400}{50} \] Calculating this gives: \[ \frac{2400}{50} = 48 \] ### Step 2: Calculate \(\frac{\sum x_i}{N}\) \[ \frac{\sum x_i}{N} = \frac{250}{50} \] Calculating this gives: \[ \frac{250}{50} = 5 \] ### Step 3: Calculate \(\left(\frac{\sum x_i}{N}\right)^2\) Now, we square the result from Step 2: \[ \left(\frac{\sum x_i}{N}\right)^2 = 5^2 = 25 \] ### Step 4: Substitute values into the variance formula Now we substitute the values we calculated into the variance formula: \[ \sigma^2 = 48 - 25 \] Calculating this gives: \[ \sigma^2 = 23 \] ### Conclusion Thus, the variance of the distribution is: \[ \text{Variance} = 23 \] ### Final Answer The correct answer is option D: 23. ---
Promotional Banner

Topper's Solved these Questions

Similar Questions

Explore conceptually related problems

If for a distribution sum(x-5)=3,sum(x-5)^(2)=43 and the total number of terms is 18 then mean and variance are

Let x_(1), x_(2),….,x_(n) be n observation such that sum(x_(i))^(2)=400 and sumx_(i)=40 , then a possible value of n among the following is

If for a sample of size 60, we have the following information sum(x_(i))^2=18000 and sumx_(i)=960 , then the variance is

The mean of the following frequency distribution is 57.6 and the sum of the observations is 50. Find the missing frquencies f_(1) and f_(2) :

If for a sample of size 60, we have the following information sumx_i^2=18000 \ and \ sumx_i=960 , then the variance is (a) 6.63 (b) 16 (c) 22 (d) 44

If for distribution of 18 observations sum(x_i-5)=3a n dsum(x_i-5)^2=43 , find the mean and standard deviation.

If for distribution of 18 observations sum(x_i-5)=3a n dsum(x_i-5)^2=43 , find the mean and standard deviation.

In a binomial distribution, mean is 5 and the variance is 4 . The number of trials is

A binomial distribution has mean 5 and variance 4. Find the number of trials.

The standard deviation (sigma) of variate x is the square root of the A.M. of the squares of all deviations of x from the A.M. observations. If x_i//f_i , i=1,2,… n is a frequency distribution then sigma=sqrt(1/N Sigma_(i=1)^(n) f_i(x_i-barx)^2), N=Sigma_(i=1)^(n) f_i and variance is the square of standard deviation. Coefficient of dispersion is sigma/x and coefficient of variation is sigma/x xx 100 For a given distribution of marks mean is 35.16 and its standard deviation is 19.76 then coefficient of variation is

ICSE-STATISTICS-MULTIPLE CHOICE QUESTIONS
  1. Consider the data The frequency of the upper limit of the median...

    Text Solution

    |

  2. The mean deviation for n observations x(1),x(2)…….x(n) from their medi...

    Text Solution

    |

  3. The mean deviation of the data 4,5,7,8,9,10,6 from the median is

    Text Solution

    |

  4. The mean deviation of the data 4,5,7,8,9,10,6 from the median is

    Text Solution

    |

  5. The variance of first 5 natural numbers is (i) 1 (ii) 2 (iii) 3...

    Text Solution

    |

  6. The standard deviation of first 11 nutural numbers is (i) 2 (ii) ...

    Text Solution

    |

  7. If for a distribution sum(x-7)=6 and sum(x-7)^(2)=78 and the total num...

    Text Solution

    |

  8. If for a distribution sumx(i)^2=2400 and sumx(i)=250 and the total num...

    Text Solution

    |

  9. The mean of 100 observations is 50 and their standard deviation is 5. ...

    Text Solution

    |

  10. The mean of 100 observations is 40 and their standard deviation respec...

    Text Solution

    |

  11. The mean of 5 observations is 4.4 and variance is 8.24. If three of th...

    Text Solution

    |

  12. Let x(1),x(2),x(3),……..,x(n) be n observations with mean barx and stan...

    Text Solution

    |

  13. If x(1),x(2),x(3),.........,x(n) be n observations with mean barx and ...

    Text Solution

    |

  14. Consider the numbers 1,2,3,4,5,6,7,8,9,10. If 2 is added to each numbe...

    Text Solution

    |

  15. A set of n values x(1),x(2),…….,x(n) has standard deviation sigma. The...

    Text Solution

    |

  16. A set of n value x(1),x(2),……..,x(n) has mean barx and standard deviat...

    Text Solution

    |

  17. Calculate the possible values of x, if the standard deviation of the n...

    Text Solution

    |

  18. The coefficient of variation of two distributions are 70 and 75 and th...

    Text Solution

    |

  19. The coefficient of variation of distributions are 50 and 60 and their ...

    Text Solution

    |

  20. Let x(1),x(2),……,x(n) be n observations and barx be their arithmetic m...

    Text Solution

    |