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The equation of parabola through (-1,3)...

The equation of parabola through (-1,3) and symmetric with respect to x-axis and vertex at origin is (i) `y^(2) = - 9x` (ii) ` y^(2) = 9 x ` (iii) ` y^(2) = 3 x` (iv) ` y^(2) = - 3x`

A

`y^(2) = - 9x`

B

` y^(2) = 9 x `

C

` y^(2) = 3 x`

D

` y^(2) = - 3x`

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The correct Answer is:
To find the equation of the parabola that passes through the point (-1, 3), is symmetric with respect to the x-axis, and has its vertex at the origin, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Standard Form of the Parabola**: Since the parabola is symmetric with respect to the x-axis and has its vertex at the origin, its equation can be expressed in the form: \[ y^2 = 4ax \] or \[ y^2 = -4ax \] depending on whether it opens to the right or left. 2. **Use the Given Point**: The parabola passes through the point (-1, 3). We can substitute \( x = -1 \) and \( y = 3 \) into the equation to find the value of \( a \). 3. **Substituting the Point into the Equation**: Let's use the equation \( y^2 = -4ax \) since we are looking for a parabola that opens to the left (as it is symmetric with respect to the x-axis): \[ 3^2 = -4a(-1) \] This simplifies to: \[ 9 = 4a \] 4. **Solve for \( a \)**: Rearranging the equation gives: \[ a = \frac{9}{4} \] 5. **Write the Equation of the Parabola**: Now, substituting the value of \( a \) back into the standard form: \[ y^2 = -4\left(\frac{9}{4}\right)x \] This simplifies to: \[ y^2 = -9x \] 6. **Conclusion**: Therefore, the equation of the parabola is: \[ y^2 = -9x \] The correct option is (i) \( y^2 = -9x \).
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ICSE-CONIC SECTIONS -Multiple Choice Questions
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  13. The equation of the directrix of the parabola x^(2) - 4x - 8y + 12 = ...

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