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The equation of the parabola with focu...

The equation of the parabola with focus (0,0) and directrix x + y - 4 = 0 is

A

`x^(2) + y^(2) - 2x y + 8x + 8y = 0 `

B

`x^(2) + y^(2) - 2xy + 8 x + 8 y - 16 = 0`

C

` x^(2) + y^(2) + 8 x + 8y - 16 = 0 `

D

` x^(2) + y^(2) + 2xy - 8x - 8y + 16 = 0 `

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The correct Answer is:
To find the equation of the parabola with focus at (0,0) and directrix given by the line \(x + y - 4 = 0\), we can follow these steps: ### Step 1: Understand the Definition of a Parabola A parabola is defined as the set of all points (P) that are equidistant from a fixed point (the focus) and a fixed line (the directrix). ### Step 2: Identify the Given Information - Focus (F) = (0, 0) - Directrix: \(x + y - 4 = 0\) ### Step 3: Set Up the Distance Equations Let \(P(x, y)\) be any point on the parabola. The distance from point \(P\) to the focus \(F(0, 0)\) is given by: \[ d(F, P) = \sqrt{(x - 0)^2 + (y - 0)^2} = \sqrt{x^2 + y^2} \] The distance from point \(P\) to the directrix can be calculated using the formula for the distance from a point to a line \(Ax + By + C = 0\): \[ d(P, \text{directrix}) = \frac{|Ax + By + C|}{\sqrt{A^2 + B^2}} \] For the directrix \(x + y - 4 = 0\), we have: - \(A = 1\), \(B = 1\), \(C = -4\) Thus, the distance from point \(P\) to the directrix is: \[ d(P, \text{directrix}) = \frac{|1 \cdot x + 1 \cdot y - 4|}{\sqrt{1^2 + 1^2}} = \frac{|x + y - 4|}{\sqrt{2}} \] ### Step 4: Set the Distances Equal Since the point \(P\) is equidistant from the focus and the directrix, we set the two distances equal: \[ \sqrt{x^2 + y^2} = \frac{|x + y - 4|}{\sqrt{2}} \] ### Step 5: Square Both Sides To eliminate the square root, we square both sides: \[ x^2 + y^2 = \frac{(x + y - 4)^2}{2} \] ### Step 6: Multiply Through by 2 To clear the fraction, we multiply both sides by 2: \[ 2(x^2 + y^2) = (x + y - 4)^2 \] ### Step 7: Expand the Right Side Now, we expand the right side: \[ 2(x^2 + y^2) = (x^2 + 2xy + y^2 - 8x - 8y + 16) \] ### Step 8: Rearrange the Equation Now, we rearrange the equation: \[ 2x^2 + 2y^2 = x^2 + y^2 + 2xy - 8x - 8y + 16 \] \[ 2x^2 + 2y^2 - x^2 - y^2 - 2xy + 8x + 8y - 16 = 0 \] \[ x^2 + y^2 - 2xy + 8x + 8y - 16 = 0 \] ### Final Equation Thus, the equation of the parabola is: \[ x^2 + y^2 - 2xy + 8x + 8y - 16 = 0 \]
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ICSE-CONIC SECTIONS -Multiple Choice Questions
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