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If R is a relation on the set T of all t...

If R is a relation on the set T of all triangles drawn in a plane defined by a R b iff a is congruent to b for all, a, b `in` T, then R is

A

reflexive but not transitive

B

reflexive but not symmetric

C

symmetric but not transivtive

D

equivalence relation

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The correct Answer is:
To determine the properties of the relation \( R \) defined on the set \( T \) of all triangles, where \( a R b \) if and only if triangle \( a \) is congruent to triangle \( b \), we will check if \( R \) is reflexive, symmetric, and transitive. If it satisfies all three properties, then \( R \) is an equivalence relation. ### Step 1: Check Reflexivity A relation \( R \) is reflexive if for every element \( a \) in the set \( T \), \( a R a \) holds true. - Let \( A \) be any triangle in \( T \). - By the definition of congruence, any triangle \( A \) is congruent to itself. - Therefore, \( A R A \) is true. **Conclusion:** The relation \( R \) is reflexive. ### Step 2: Check Symmetry A relation \( R \) is symmetric if whenever \( a R b \), then \( b R a \) also holds true. - Let \( A \) and \( B \) be any triangles in \( T \) such that \( A R B \) (i.e., \( A \) is congruent to \( B \)). - By the properties of congruence, if triangle \( A \) is congruent to triangle \( B \), then triangle \( B \) is also congruent to triangle \( A \). - Therefore, if \( A R B \) is true, then \( B R A \) is also true. **Conclusion:** The relation \( R \) is symmetric. ### Step 3: Check Transitivity A relation \( R \) is transitive if whenever \( a R b \) and \( b R c \), then \( a R c \) also holds true. - Let \( A, B, C \) be any triangles in \( T \) such that \( A R B \) (i.e., \( A \) is congruent to \( B \)) and \( B R C \) (i.e., \( B \) is congruent to \( C \)). - By the properties of congruence, if triangle \( A \) is congruent to triangle \( B \) and triangle \( B \) is congruent to triangle \( C \), then triangle \( A \) is also congruent to triangle \( C \). - Therefore, \( A R C \) is true. **Conclusion:** The relation \( R \) is transitive. ### Final Conclusion Since the relation \( R \) is reflexive, symmetric, and transitive, it is an equivalence relation. ### Answer Thus, \( R \) is an equivalence relation. ---
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