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If in matrix [{:(3,2x,-5),(-4,0,y),(-5,3...

If in matrix `[{:(3,2x,-5),(-4,0,y),(-5,3,7):}]` is symmetric, then :

A

`x=2, y=-3`

B

`x=2 y=3`

C

`x=-2, y=-3`

D

`x=-2y,y=3`

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AI Generated Solution

The correct Answer is:
To determine the values of \( x \) and \( y \) in the given matrix \[ A = \begin{pmatrix} 3 & 2x & -5 \\ -4 & 0 & y \\ -5 & 3 & 7 \end{pmatrix} \] we need to use the property of symmetric matrices, which states that a matrix is symmetric if it is equal to its transpose, i.e., \( A = A^T \). ### Step 1: Write the Transpose of the Matrix The transpose of matrix \( A \) is obtained by swapping rows with columns: \[ A^T = \begin{pmatrix} 3 & -4 & -5 \\ 2x & 0 & 3 \\ -5 & y & 7 \end{pmatrix} \] ### Step 2: Set the Matrix Equal to Its Transpose Since \( A \) is symmetric, we have: \[ \begin{pmatrix} 3 & 2x & -5 \\ -4 & 0 & y \\ -5 & 3 & 7 \end{pmatrix} = \begin{pmatrix} 3 & -4 & -5 \\ 2x & 0 & 3 \\ -5 & y & 7 \end{pmatrix} \] ### Step 3: Equate Corresponding Elements From the equality of the two matrices, we can equate corresponding elements: 1. From the first row, second column: \[ 2x = -4 \] 2. From the second row, third column: \[ y = 3 \] ### Step 4: Solve for \( x \) Now, we solve the equation \( 2x = -4 \): \[ x = \frac{-4}{2} = -2 \] ### Step 5: State the Values of \( x \) and \( y \) Thus, we find: \[ x = -2 \quad \text{and} \quad y = 3 \] ### Final Answer The values of \( x \) and \( y \) are: \[ x = -2, \quad y = 3 \] ---
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ICSE-MATRICES-MULTIPLE CHOICE QUESTION (Competency based questions)
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