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If A is a skew-symmetric matrix such tha...

If A is a skew-symmetric matrix such that `(A^(n))'=kA^(n), n in N`, then the value of k is

A

1

B

`-1`

C

`(-1)^(n)`

D

n

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of \( k \) in the equation \( (A^n)' = kA^n \) where \( A \) is a skew-symmetric matrix. ### Step-by-step Solution: 1. **Understand Skew-Symmetric Matrix**: A matrix \( A \) is skew-symmetric if \( A' = -A \). 2. **Apply the Property of Transpose**: For any matrix \( A \), the transpose of the product of matrices follows the rule: \[ (AB)' = B'A' \] For powers of a matrix, we have: \[ (A^n)' = (A \cdot A \cdots A)' = A' \cdot A' \cdots A' = (A')^n \] 3. **Substituting the Skew-Symmetric Property**: Since \( A' = -A \), we can substitute this into our equation: \[ (A^n)' = (-A)^n = (-1)^n A^n \] 4. **Set Up the Given Equation**: The problem states that: \[ (A^n)' = k A^n \] From our previous step, we have: \[ (A^n)' = (-1)^n A^n \] 5. **Equate the Two Expressions**: Now, we can equate the two expressions we have for \( (A^n)' \): \[ k A^n = (-1)^n A^n \] 6. **Solve for \( k \)**: Since \( A^n \) is not the zero matrix (as \( A \) is skew-symmetric and not the zero matrix), we can divide both sides by \( A^n \): \[ k = (-1)^n \] ### Conclusion: Thus, the value of \( k \) is: \[ k = (-1)^n \]
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