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If P(A ) =4/5 and P( A cap B) =7/10 then...

If `P(A ) =4/5 and P( A cap B) =7/10` then P(B/A) is equal to

A

`1/10`

B

`1/8`

C

`7/8`

D

`17/20`

Text Solution

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The correct Answer is:
To find \( P(B|A) \), we can use the formula for conditional probability: \[ P(B|A) = \frac{P(A \cap B)}{P(A)} \] ### Step 1: Identify the given values We have: - \( P(A) = \frac{4}{5} \) - \( P(A \cap B) = \frac{7}{10} \) ### Step 2: Substitute the values into the formula Now, substitute the values into the conditional probability formula: \[ P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{7}{10}}{\frac{4}{5}} \] ### Step 3: Simplify the fraction To simplify the fraction, we can multiply by the reciprocal of the denominator: \[ P(B|A) = \frac{7}{10} \times \frac{5}{4} \] ### Step 4: Perform the multiplication Now, perform the multiplication: \[ P(B|A) = \frac{7 \times 5}{10 \times 4} = \frac{35}{40} \] ### Step 5: Simplify the result Now, simplify \( \frac{35}{40} \): \[ P(B|A) = \frac{7}{8} \] ### Final Answer Thus, the probability \( P(B|A) \) is: \[ \boxed{\frac{7}{8}} \]
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