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There are two bags . One bag contains 3 ...

There are two bags . One bag contains 3 white balls and 2 black balls . The other box contains 7 white and 3 balck balls , If a bag is selected at random and from it , then a ball is drawn then the probability that the ball is black is .

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To find the probability of drawing a black ball from the two bags, we can follow these steps: ### Step 1: Understand the Problem We have two bags: - **Bag 1**: Contains 3 white balls and 2 black balls (Total = 5 balls) - **Bag 2**: Contains 7 white balls and 3 black balls (Total = 10 balls) ### Step 2: Define Events Let: - \( E_1 \): Event of choosing Bag 1 - \( E_2 \): Event of choosing Bag 2 - \( A \): Event of drawing a black ball ### Step 3: Calculate the Probability of Choosing Each Bag Since a bag is selected at random, the probabilities are: - \( P(E_1) = \frac{1}{2} \) - \( P(E_2) = \frac{1}{2} \) ### Step 4: Calculate the Probability of Drawing a Black Ball from Each Bag - For **Bag 1**: The probability of drawing a black ball: \[ P(A | E_1) = \frac{\text{Number of black balls in Bag 1}}{\text{Total number of balls in Bag 1}} = \frac{2}{5} \] - For **Bag 2**: The probability of drawing a black ball: \[ P(A | E_2) = \frac{\text{Number of black balls in Bag 2}}{\text{Total number of balls in Bag 2}} = \frac{3}{10} \] ### Step 5: Apply the Total Probability Theorem The total probability of drawing a black ball \( P(A) \) can be calculated as: \[ P(A) = P(E_1) \cdot P(A | E_1) + P(E_2) \cdot P(A | E_2) \] Substituting the values: \[ P(A) = \left(\frac{1}{2} \cdot \frac{2}{5}\right) + \left(\frac{1}{2} \cdot \frac{3}{10}\right) \] ### Step 6: Simplify the Expression Calculating each term: - First term: \[ \frac{1}{2} \cdot \frac{2}{5} = \frac{2}{10} = \frac{1}{5} \] - Second term: \[ \frac{1}{2} \cdot \frac{3}{10} = \frac{3}{20} \] Now, we need a common denominator to add these fractions: - The common denominator of 5 and 20 is 20. - Convert \( \frac{1}{5} \) to have a denominator of 20: \[ \frac{1}{5} = \frac{4}{20} \] Now, add the two fractions: \[ P(A) = \frac{4}{20} + \frac{3}{20} = \frac{7}{20} \] ### Final Answer The probability that the drawn ball is black is: \[ \boxed{\frac{7}{20}} \] ---
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